Perl preprocessor appended to other variable -

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i trying write following code, want $varpre1 $var1 , $varpre2 $var2 after preprocessor evaluated, not working. there work around?

#define pre1 1 #define pre2 2  $var1 = 10; $var2 = 20;  print $varpre1; print $varpre2;

what wrote doesn't make sense c preprocessor, since varpre1 parsed 1 token.

what want sort of possible, using called symbolic references, a bad idea.

$pre1 = '1'; $pre2 = '2'; $var1 = 10; $var2 = 20; print ${'var' . $pre1};   #   same print $var1 => 10 print ${'var' . $pre2};

this not work under use strict refs. bad idea not use strict refs.


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