regex - Python: Error in re.compile() function for double digits -

-

this regex needs find "1x" or "x1" must able find double digits such "10x" , "x11".

leverage_match = re.compile(r"\d+x|x\d+", flags=re.ignorecase)

according regex101.com above regex should sufficient capture entire numbers for:

import pandas pd import re  df = pd.dataframe(["bull estox 11x s", "bull estox x12 s"], columns=["name"])  name "bull estox 11x s" "bull estox x12 s"

however, code below returns 1 digit, e.g. "11x" becomes "1x".

leverage_match = re.compile(r"\d+x|x\d+", flags=re.ignorecase) #<- same seen above  def f(value):      f2 = lambda x: leverage_match.findall(x)[0] if len(leverage_match.findall(x)) > 0 else ""      leverage = f2(value)      if leverage != "":         return "{}".format(leverage)      if leverage[0].replace("x","x") == "x":         leverage = leverage[1]+leverage[0].replace('x','x')  df["description"] = df["name"].map(lambda x:f(x))

----------

update: complete code, assure did not leave essential out:

import pandas pd import re  df = pd.dataframe(["bull estox 11x s", "bull estox x12 s"], columns=["name"])  description_map = {"estox":"euro stoxx 50"} underlying_match = re.compile(r"\s(\s+)\s") leverage_match = re.compile(r"\d+x|x\d+", flags=re.ignorecase)  def f(value):      f1 = lambda x: description_map[underlying_match.findall(x)[0]] if underlying_match.findall(x)[0] in description_map else ""     f2 = lambda x: leverage_match.findall(x)[0] if len(leverage_match.findall(x)) > 0 else ""     f3 = lambda x: "-" if "bear" in x else "-" if "short" in x else ""      underlying = f1(value)     leverage = f2(value)     sign = f3(value)      statement = "tracks " + underlying      if underlying == "":         if sign == "-" , leverage == "":             return statement + "{}".format("inversely.")         if sign == "-" , leverage != "":             return statement + "{} {}{} leverage.".format("inversely", sign, leverage)         if sign == "" , leverage != "":             return statement + "with {}{} leverage.".format(sign, leverage)         else:             return "tracks"      if leverage[0].replace("x","x") == "x":         leverage = leverage[1]+leverage[0].replace('x','x')      if leverage != "" , sign == "-":         statement += " {} {}{} leverage.".format("inversely", sign, leverage)     elif leverage != "" , sign == "":         statement += " {} leverage.".format(leverage)     else:         if sign == "-":             statement += " {} ".format("inversely")      return statement  df["description"] = df["name"].map(lambda x:f(x))  print df

i think gave wrong example, following df

df = pd.dataframe(["bull axp 11x s", "bull axp x11 s"], columns=["name"])

the output follows

             name                                 description 0  bull axp 11x s  tracks american express 11x leverage. 1  bull axp x11 s   tracks american express 1x leverage.

and x11 becomes 1x because there error in logic of our code in following section:

if leverage[0].replace("x","x") == "x":         leverage = leverage[1]+leverage[0].replace('x','x')

it must instead should have been follows:(update)

if leverage[0].replace("x","x") == "x":         leverage = ''.join(leverage[1:])+leverage[0].replace('x','x')

if fix , output expected , follows:

             name                                 description 0  bull axp 11x s  tracks american express 11x leverage. 1  bull axp x11 s  tracks american express 11x leverage.

complete code

import pandas pd import re  df = pd.dataframe(["bull estox 11x s", "bull estox x12 s"], columns=["name"])  description_map = {"estox":"euro stoxx 50"} underlying_match = re.compile(r"\s(\s+)\s") leverage_match = re.compile(r"\d+x|x\d+", flags=re.ignorecase)  def f(value):      f1 = lambda x: description_map[underlying_match.findall(x)[0]] if underlying_match.findall(x)[0] in description_map else ""     f2 = lambda x: leverage_match.findall(x)[0] if len(leverage_match.findall(x)) > 0 else ""     f3 = lambda x: "-" if "bear" in x else "-" if "short" in x else ""      underlying = f1(value)     leverage = f2(value)     sign = f3(value)      statement = "tracks " + underlying      if underlying == "":         if sign == "-" , leverage == "":             return statement + "{}".format("inversely.")         if sign == "-" , leverage != "":             return statement + "{} {}{} leverage.".format("inversely", sign, leverage)         if sign == "" , leverage != "":             return statement + "with {}{} leverage.".format(sign, leverage)         else:             return "tracks"      if leverage[0].replace("x","x") == "x":         leverage = ''.join(leverage[1:])+leverage[0].replace('x','x')      if leverage != "" , sign == "-":         statement += " {} {}{} leverage.".format("inversely", sign, leverage)     elif leverage != "" , sign == "":         statement += " {} leverage.".format(leverage)     else:         if sign == "-":             statement += " {} ".format("inversely")      return statement  df["description"] = df["name"].map(lambda x:f(x))  print df

Comments

Post a Comment

Popular posts from this blog

python - No exponential form of the z-axis in matplotlib-3D-plots -

-
Image
i have similar problem described in how prevent numbers being changed exponential form in python matplotlib figure : i don't want (in special case) weird scientific formatting of axis. problem different have problem @ z -axis. 2-d plots can use ax.get_yaxis().get_major_formatter().set_useoffset(false) . , there no function ax.get_zaxis() what use format z -axis same way? edit: example: from mpl_toolkits.mplot3d import axes3d import numpy np import sys import matplotlib import matplotlib.pyplot pyplot def func(xi, ti): res = 10e3 + np.cos(ti) * np.sin(xi) return res if __name__ == '__main__': timespacing = 20 timestart = 0 timeend = 1 time = np.linspace(timestart, timeend, timespacing) widthspacing = 50 widthstart = 0 widthend = 3 width = np.linspace(widthstart, widthend, widthspacing) reslist = [] matplotlib.rcparams['legend.fontsize'] = 10 fig = pyplot.figure() ax = fig.gca(projection = '3d...
Read more

php - Best Light server (Linux + Web server + Database) for Raspberry Pi -

-
i install web server database on raspberry pi (little computer). computer has 1gb ram. i want know best combination: linux distribution , web server , dbms run local server multiple users minimal latency, use php on server. , best settings performance , not have bugs (memory usage, disable plugin, disable service, etc)? i thought light debian , lighttpd server , sqlite database. solution? i think lighttpd + sqlite great choice. linux distro, debian @ centos or tiny core linux , although i'm not sure of compatibility pi. obviously, can't go wrong raspbian if want use in production , more stable performance, few more pi's , set them in cluster .
Read more

c# - "Newtonsoft.Json.JsonSerializationException unable to find constructor to use for types" error when deserializing class -

-
i developing app in xamarin android. have splash screen serialize class , pass mainactivity using intent . when try deserialize in mainactivity error message : "serializationexception unable find constructor use types" serialization : void loaddata() { currency currency = new currency(this); intent = new intent(this, typeof(mainactivity)); intent.putextra("currency", newtonsoft.json.jsonconvert.serializeobject(currency)); startactivity(intent); } deserialization : cur = newtonsoft.json.jsonconvert.deserializeobject<currency> (intent.getstringextra("currency")); // error here class constructor : public currency(context context) { thiscontext = context; } i began experiencing problem after added parameter context context constructor. has caused this? how can solve it? possible serialize/deserialize class has parameters? you need have empty constructor in currency class in order deserialize it. ...
Read more