android - how to sort Arraylist of string having integer values in java -

i having string list consists of integer values. want sort in ascending in descending order.

arraylist<string> = new arraylist<string>(); a.add("1435536000000"); a.add("1435622400000");  system.out.println("before : " + a); collections.sort(a, new comparatorofnumericstring()); system.out.println("after : " + a); 

my comparatorofnumericstring class -

public class comparatorofnumericstring implements comparator<string> {      @suppresslint("newapi")     @override     public int compare(string lhs, string rhs) {         int i1 = integer.parseint(lhs);         int i2 = integer.parseint(rhs);         return integer.compare(i1, i2);     }  }   

any 1 having idea how sort strings having integer values in java?

thanks lot!! in advance!!

the better way add integers/long in arraylist , sorting using collections.sort(a) method.

if still want using string, need make modifications. please find below code same:

import java.util.arraylist; import java.util.collections; import java.util.comparator;  public class input implements comparator<string>{     public static void main(string[] args) {         arraylist<string> = new arraylist<string>();         a.add("1435536000000");         a.add("1435622400000");         a.add("1");         a.add("10");         a.add("20");         a.add("15");         a.add("1435622400010");          system.out.println("before : " + a);         collections.sort(a, new input());         system.out.println("after : " + a);           }      public int compare(string lhs, string rhs) {     long i1 = long.parselong(lhs);     long i2 = long.parselong(rhs);     return (int) (i1-i2);    }  }