MYSQL PHP PDO Fill table with database data -


i want give out every line in database. seems working returns first column.

screenshot note: there values empty fields in database!

$columns = "ticket, last_modified_date, requester"; 

heres code:

    function getticket($columns){     echo($columns);     global $db_host, $db_name, $db_user, $db_pass;     $db = new pdo("mysql:host=$db_host;dbname=$db_name;charset=utf8", "$db_user", "$db_pass");     $result = $db->prepare("select $columns tickets"); if ($result->execute()){     echo("<b>successfully!</b><br><br>");      $rows = $result->fetchall(pdo::fetch_assoc);     $col_names = explode(',', $columns); foreach($rows $row){     echo("<tr>"); foreach($col_names $col_name){ if (!isset($row[$col_name])){     continue;     }     echo("<td>".$row[$col_name]."</td>");     }     echo("</tr>");         }     } else{     echo("<b>failed!</b><br><br>");     }     $db = null; } 

there couple of issues here, first should use ->fetchall() return result rows in 1 hit array.

second overwriting $result statement handle row being returned ->fetch

function getticket($columns){       global $db_host, $db_name, $db_user, $db_pass;      $db = new pdo("mysql:host=$db_host;dbname=$db_name;charset=utf8", "$db_user", "$db_pass");      $result = $db->prepare("select $columns tickets");      if ($result->execute()){         echo("<b>successfully!</b><br><br>");          // changes here         $rows = $result->fetchall(pdo::fetch_assoc);          $col_names = explode(',', $columns);  //make array of csv          foreach($rows $row){              foreach( $col_names $col_name ) {                 echo '<td>' . $row[$col_name] . '</td>';             }         }     }else{         echo("<b>failed!</b><br><br>");     }     $db = null; } 

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