bash - Passing pipe output to Test command -

i'm confused test command syntax. goal check if file exists, file path formed sed command.

so, try, example:

echo '~/test111' | sed s/111/222/g | test -f && echo "found" || echo "not found"

but command returns "found". doing wrong?

with currenty approach, saying:

test -f && echo "yes" || echo "no"

since test -f returns true default, getting "yes":

$ test -f $ echo $? 0

the correct syntax test -f "string":

so want say:

string=$(echo '~/test111'|sed 's/111/222/g') test -f "$string" && echo "found" || echo "not found"

which can compacted into:

test -f "$(echo '~/test111'|sed 's/111/222/g')" && echo "found" || echo "not found"

but looses readability.

and can use xargs perform given action in name given previous pipe:

echo '~/test111'|sed 's/111/222/g' | xargs test -f && echo "found" || echo "not found"

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