SQL Server, Count Consecutive Weeks Record Has Been in Top 5 -

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i have complicated query:

select rs.name, rs.sumhits, rs.weeknumber from(     select name, weeknumber, sum(hits) sumhits, rank()     on (partition weeknumber order sum(hits) desc) rank (     select     name,     datediff     (         day,         (select dateadd(wk, datediff(wk,0,(select min(table2.date) table2)), 0)),         (table2.date)     ) / 7 weeknumber,     hits     table1     inner join table2 on table1.nameid = name.id ) group name, weeknumber ) rs rank <= 5 order weeknumber desc

which provides me top 5 "names" "hits" each week.

i add field calculates number of consecutive weeks each name in week's top 5 has been in top five. so, column have value of 1 if name in week's top 5 not in last week's, value of 3 if name week's top 5 had been in top 5 previous 2 weeks, etc.

what best way accomplish this?

you think of query cte , add further information in follow-up ctes or final select:

something this:

with mycte ( query here!!! ) select *, furtherdata mycte

but - commented - query seems "enhanceable" :-) maybe post sample data , expected result...


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