Finding a multiple function keeps returning true and is there a simpler way to write this function in python -
this question has answer here:
def is_multiple(m, n): """ >>> is_multiple(12, 3) true >>> is_multiple(12, 4) true >>> is_multiple(12, 5) false >>> is_multiple(12, 6) true >>> is_multiple(12, 7) false """ c = m / n d = int(m / n) if (c-d)== 0: return true elif (c-d)!= 0: return false i trying make function decides if m multiple of n. can use have learned functions, if/else, if/elif/else statements, boolean expressions , simple things that. have not gotten for, while, do/while expressions yet. code keeps returning true false in 2 cases. why keep returning true, , there more simpler way write function finding multiple of number?
updated code:
def is_factor(f,n): """ >>> is_factor(3, 12) true >>> is_factor(5, 12) false >>> is_factor(7, 14) true >>> is_factor(2, 14) true >>> is_factor(7, 15) false """ if n % f == 0: return true else: return false so code can used find multiple of number also?
correct updated code produces correct result:
def is_multiple(m, n): """ >>> is_multiple(12, 3) true >>> is_multiple(12, 4) true >>> is_multiple(12, 5) false >>> is_multiple(12, 6) true >>> is_multiple(12, 7) false """ c = float (m) / n d = m / n if (c-d)== 0: return true else: return false
your is_factor looks correct. simplify to
def is_factor(f, n): return n % f == 0 if want check if x multiple of y, same saying y factor of x. thus, can do
def is_multiple(m, n): return is_factor(n, m) 
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