r - Check if a column is na in a list -

i trying check if of data frame in list has column entries na.

i tried lapply(df,function(x)all(is.na(df))) , works fine check columns. how can check if in below list, first column na.

i tried lapply(df[,1],function(x)all(is.na(df[,1]))) not correct way do

[[1]]              id mas5.signalintensity detectioncalls     p.value 1     1007_s_at           3242.90209              p 0.000218932 2       1053_at            377.81481              p 0.017000453 3        117_at            114.88743              0.066864977 4        121_at           8739.03257              p 0.000218932   [[2]]              id mas5.signalintensity detectioncalls     p.value 1            na            134.40764              p 0.000561751 2            na            453.34875              p 0.002227740 3            na            706.34996              0.066864977 4            na            102.51459              0.089405078  [[3]]              id mas5.signalintensity detectioncalls     p.value 1     1007_s_at          7015.297075              p 0.000218932 2       1053_at           677.459859              p 0.011447358 3        117_at           180.568654              0.267462560 4        121_at          1693.426847              p 0.006531992 5     1255_g_at           181.221325              0.339557900 

try

 sapply(lst, function(x) any(colsums(!is.na(x))==0))  #[1]  true false  true 

update

if want check particular column, e.g. column 2

sapply(lst, function(x) all(is.na(x[,2]))) #[1] false false  true 

or

sapply(lst, function(x) sum(!is.na(x[,2]))==0) #[1] false false  true 

data

 df <- data.frame(col1= na, col2=1:5, col3=c(1:3,na, na))  df1 <- data.frame(col1=1:5, col2=6:10, col3=11:15)  df2 <- data.frame(col1=c(na,2), col2= na, col3=c(2,4))  lst <- list(df, df1, df2)