bash - command line argument from file content with quote -

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i have file containing command line arguments pass script.

but file contain element such "param 1" param2 param3.

let's call file arguments test.tmp , script file script.sh.

if do:

script.sh -p `cat test.tmp` -other_params 1 2 3

the script.sh receives after p:

  1. "param
  2. 1"
  3. param2
  4. param3

but like:

  1. param 1
  2. param2
  3. param3

any idea?

small precision: assume script.sh not modifiable. solution must take place in shell.

assumption: test.tmp needs contain parameter per line approach.

you may use xargs linefeed delimiter:

cat test.tmp | xargs -d '\n' script.sh -p

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